# Air Max Edge

**max high physics help?**

*Antonia was standing at the edge of a vertical cliff and threw stones at the top at an angle of 6o degrees to the horizontal. Leaf stone Antonia* hands with speed v = 80m / s. The time between a rock and hit the left hand sea Antonia 3.0sec. Acceleration of free fall g 10m / s * 2 and all distance measurements taken from a point where the stone left hand Antonia. Neglecting air resistance, calculate: A. The maximum height reached by a stone. B. horizontal distance traveled by the stone.

Antonia should play baseball, 80 m / s is the speed of 288 km / hour. The stone was thrown at an angle of 6 degrees to the horizontal so that it has vertical and horizontal velocity Vh VV speed as vv = 80 * Sin (6) / s = 8.36 m / s Vh = cos (6) 80 * / s = 79.6 m / s With a vertical velocity 8.36m / s maximum height is calculated using the speed and distance equation V = at + VV and the maximum height, V = 0 then 0 =- 10T + 8.36 t = 0.836 s D = 1/2at VVT ^ 2 + D = 1 / 2 (-10) ^ 2 + 0.836 8,36 * 0,836 = 7.0 m So the maximum height is 7m And during the flight of 3 seconds is the horizontal distance of 3 Vh x = 3x79.6 m = 477.6 (what great pitchers!).

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